How do you find the exact values of six trigonometric functions of t given (sqrt 3/2, 1/2)?

1 Answer
Jun 25, 2015

sin(t) = 1/2;color(white)("XXXX")cos(t)=sqrt(3)/2;color(white)("XXXX")tan(t)=1/sqrt(3)
csc(t)=2;color(white)("XXXX")sec(t)=2/sqrt(3);color(white)("XXXX")cot(t)=sqrt(3)

Explanation:

Assuming the point given is the terminal point of an angle, t, in standard Cartesian coordinate position,
the angle is 30^o and the six trigonometric values can be read directly from the image below, base on the definition of those functions.
enter image source here