How do you find the exact values of #sintheta# and #tantheta# when #costheta=1/2#?

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How do you find the exact values of #sintheta# and #tantheta# when #costheta=1/2#?

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Answer 1 · 2017-02-28T04:09:37

Use trig table of special arcs and unit circle -->
#cos t = 1/2# --> #t = +- pi/3#
a. When #t = pi/3# -->
#sin (pi/3) = sqrt3/2#
#tan (pi/3) = sqrt3#
b. When #t = - pi/3# -->
#sin (- pi/3) = - sqrt3/2#
#tan (- pi/3) = - sqrt3#

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How do you find the exact values of #sintheta# and #tantheta# when #costheta=1/2#?

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