How do you find the exact value of #cos(pi/6)#?

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Answer 1 · 2017-03-16T12:43:10

I tried a "geometrical" approach:

Have a look:
enter image source here

Answer 2 · 2017-03-16T12:59:30

#0.866025403#

#cos(pi/6)# Radians

#cancelpi^color(red)1/cancel6 xx cancel180^color(red)30/cancelpi^color(red)1# degrees

#:.cos30°#

#:.cos30°=0.866025403#