How do you find the exact value of $5(costheta-1)=6+costheta$ in the interval $0<=theta<2pi$ ?

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Answer 1 · 2017-01-23T01:04:36

equation insolvable

5(cos t - 1) = 6 + cos t
5cos t - 5 = 6 + cos t
4cos t = 11
$cos t = 11/4 = 2.75$
Problem insolvable because cos t must be $<= 1$

How do you find the exact value of 5(costheta-1)=6+costheta5(costheta-1)=6+costheta in the interval 0<=theta<2pi0<=theta<2pi?