How do you find the exact value of #2sin^2theta-tanthetacottheta=0# in the interval #0<=theta<360#?
1 Answer
Dec 17, 2016
Explanation:
We use the identities
#2sin^2theta - sintheta/costheta*costheta/sintheta = 0#
#2sin^2theta - 1 = 0#
#2sin^2theta = 1#
#sin^2theta = 1/2#
#sintheta = +-1/sqrt(2)#
#theta = 45˚, 135˚, 225˚ and 315˚#
Hopefully this helps!
