How do you find the exact value of $2 sec x = 2 + sec x$ $2secx=2+secx$ in the interval $0 \leq x < 360$ $0<=x<360$ ?

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Answer 1 · 2017-01-29T11:14:04

Solution : In interval $0 \leq x \leq 360, x = 30^{0} or x = 300^{0}$ $0 <= x <= 360 , x = 30^0 or x= 300^0$

$2 secx = 2 +sec x or 2 secx -sec x =2 or sec x =2 or 1/cosx=2 or cosx =1/2 ; cos 60 =1/2 and cos (360-60) =1/2 :. x = 30^0 or x= 300^0$

Solution : In interval $0 <= x <= 360 , x = 30^0 or x= 300^0$ [Ans]

How do you find the exact value of 2secx=2+secx2secx=2+secx2secx=2+secx in the interval 0<=x<3600≤x<3600<=x<360?