How do you find the exact value of $2cosx-secx=0$ in the interval $0<=x<360$ ?

Nov 23, 2016

$2cosx - 1/cosx = 0$

$2cos^2x - 1 = 0$

$cos^2x= 1/2$

$cosx= +-1/sqrt(2)$

$x = 45˚, 135˚, 225˚, 315˚$

Hopefully this helps!

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