How do you find the exact value for #cos 240#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Alan P. May 24, 2015 it equals #(-1/2)# because #cos(60^@) = 1/2# Explanation: The reference angle for #240^@# is #60^@# (since #240^@ = 180^@ + 60^@#) #60^@# is an angle of one of the standard triangles with #cos(60^@) = 1/2# #240^@# is in the 3rd quadrant so (either by CAST or noting that the "x-side" of the associate triangle is negative) #cos(240^@) = -cos(60^@)# #cos(240^@) = -1/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 89592 views around the world You can reuse this answer Creative Commons License