How do you find the equation of the tangent line to the graph of #y = ln x^2# at the point (2, ln 4)? Calculus Derivatives Tangent Line to a Curve 1 Answer Bdub Mar 10, 2016 #y-ln4=1(x-2)# Explanation: #y=2lnx#->use property #log_bx^n = nlog_bx# #y'=2*1/x = 2/x=2/2 = 1# #y-ln4=1(x-2)# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 4174 views around the world You can reuse this answer Creative Commons License