How do you find the equation of the tangent line of #y= x^7- 6x^5-3# at x=1? Calculus Derivatives Tangent Line to a Curve 1 Answer Anjali G May 15, 2017 #y=-23(x-1)-8# Explanation: #y=x^7-6x^5-3# #y(1) = (1)-6(1)-3=-8# #dy/dx = 7x^6-30x^4# #dy/dx|_(x=1) = 7(1)-30(1)# #=-23# Equation of tangent line: #y=-23(x-1)-8# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1494 views around the world You can reuse this answer Creative Commons License