How do you find the equation of the line that passes through the point (1, -5). and is perpendicular to the line #y=-1/2x+4#?

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Answer 1 · 2016-12-26T05:16:04

The required equation is #y=2x-7#

Given -

#y=-1/2x+4#

Slope of the given line #m_1=-1/2#

Slope of the perpendicular line #m_2=-1 xx 1/(m_1)#

#m_2=-1xx (-2/1)=2#

Then -

Let the equation of the required line be -

#y=mx+c#

Given the point #(1, -5)# we have to find the value of #c#

#2 xx 1+c=-5#
#c=-5-2=-7#

The required equation is #y=2x-7#