# How do you find the equation of the line perpendicular to y+5=3(x-2) that passes through the point (6, 2)?

##### 2 Answers

Let,the equation of line be

Now,arranging the given equation in the above mentioned form to get its slope,

Given,

So,its slope is

Now,for two lines to be mutually perpendicular,their product of slope must be

So,

or.

So,our required line equation becomes,

Now,given,that the line passes through

So,

or,

So,the equation of the line is

or,

Or

Or

Or

#### Explanation:

There are several forms for the equation of a straight line:

Another is

where

This is exactly the form we have for the given equation:

If lines are perpendicular, the product of their slopes is

One is the negative reciprocal of the other, so:

Using

Or in another form:

Or even