How do you find the equation of line through point (-6, -1) perpendicular to line #5x-3y=2#?
1 Answer
Dec 20, 2017
Explanation:
#"given the slope m of a line then the slope of a line"#
#"perpendicular to it is"#
#•color(white)(x)m_(color(red)"perpendicular")=-1/m#
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#"rearrange "5x-3y=2" into this form"#
#rArry=5/3x-2/3larr" with "m=5/3#
#rArrm_(color(red)"perpendicular")=-1/(5/3)=-3/5#
#rArry=-3/5x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute "(-6,-1)#
#"into the partial equation"#
#-1=18/5+brArrb=-23/5#
#rArry=-3/5x-23/5larrcolor(red)"in slope-intercept form"#
