How do you find the equation for tangent line to #f(x) = (x-1)^2# at the point where x = 2?

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Answer 1 · 2018-04-23T02:06:48

#y = 2x -3#

#f'(x) = 2 (x-1)#

#m = f'(2) = 2#

#y = mx + b = 2x + b#

#f(2) = 2 f'(2) + b#

#1 = 2(2) + b#

#b = -3#

#y = 2x -3#

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