How do you find the domain of $y=sqrt(9+x)$ ?

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How do you find the domain of $y=sqrt(9+x)$ ?

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Answer 1 · 2015-05-09T15:46:41

Assuming we are restricted to Real numbers
the Domain of $y=sqrt(9+x)$ are all Real values of $x$ for which this equation is defined (within the Reals).

$sqrt(9+x$ is defined for all values $x>=-9$

Therefore the Domain of $y=sqrt(9+x)$
is $[-9,+oo)$

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How do you find the domain of $y=sqrt(9+x)$ ?

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How do you find the domain of $y=sqrt(9+x)$ ?