How do you find the domain of the function in interval notation for $g(x)= sqrtx/(x^2+x-90)$ ?

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Answer 1 · 2015-04-07T20:19:30

$g(x) = sqrt(x)/(x^2+x-90)$
$= sqrt(x)/((x+10)(x-9)$

Restrictions based by the numerator
$x>=0$

Restrictions place by denominator
$x!= -10$ (this is eliminated by the restriction of the numerator)
and $x!= 9$

In interval notation
Domain of $g(x) = {[0,9),(9,+oo]}$

How do you find the domain of the function in interval notation for g(x)= sqrtx/(x^2+x-90)g(x)= sqrtx/(x^2+x-90)?