How do you find the domain of $f(x) = (x+3)/(2x-5)$ ?

Question

1649 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-06T22:40:11

The domain is the set of all the $x-$ values.
$x epsilon RR, x != -5/2$

We have to decide if there are any values of $x$ which are invalid.

Looking at the numerator, $x + 3$ , there is no problem or restriction for a value of $x$ . The numerator can even be equal to 0

However, the denominator of a fraction may not be equal to 0.
If $2x+ 5 =0$ , then the value of $x$ is $-5/2$

So, for the domain, $x epsilon RR, x != -5/2$

This reads as " $x$ may be any real number except $-5/2$ .

How do you find the domain of f(x) = (x+3)/(2x-5)f(x) = (x+3)/(2x-5)?