How do you find the domain and range for $y = - .566021616 {(x - 6)}^{2} + 3.7$ $y = -.566021616 (x - 6) ^2 + 3.7$ ?

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How do you find the domain and range for $y = - .566021616 {(x - 6)}^{2} + 3.7$ $y = -.566021616 (x - 6) ^2 + 3.7$ ?

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Answer 1 · 2015-09-02T20:19:32

See below.

Explanation:

$y = - 0.566021616 {(x - 6)}^{6} + 3.7$ $y = -0.566021616(x-6)^6 +3.7$

$x$ $x$ can take any value, so the domain is all real numbers.

When $x = 6$ $x=6$ , ${(x - 6)}^{6} = 0$ $(x-6)^6=0$ , and $y = 3.7$ $y = 3.7$ .

When $x \neq 6$ $x ≠ 6$ , ${(x - 6)}^{6}$ $(x-6)^6$ is a positive number, and $- 0.566021616 {(x - 6)}^{6}$ $-0.566021616(x-6)^6$ is a negative number.

So $3.7$ $3.7$ is the maximum value of $y = - 0.566021616 {(x - 6)}^{6} + 3.7$ $y = -0.566021616(x-6)^6 +3.7$ .

The range is all real numbers less than or equal to $3.7$ $3.7$ .

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How do you find the domain and range for $y = - .566021616 {(x - 6)}^{2} + 3.7$ $y = -.566021616 (x - 6) ^2 + 3.7$ ?

1 Answer

Explanation:

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Science

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How do you find the domain and range for y=−.566021616(x−6)2+3.7y = -.566021616 (x - 6) ^2 + 3.7?

1 Answer

Explanation:

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How do you find the domain and range for $y = - .566021616 {(x - 6)}^{2} + 3.7$ $y = -.566021616 (x - 6) ^2 + 3.7$ ?