How do you find the distance from the line with equation $y = 9 x - 3$ $y=9x-3$ to the point at (-3,2)?

Question

How do you find the distance from the line with equation $y = 9 x - 3$ $y=9x-3$ to the point at (-3,2)?

1 Answer

Impact of this question

2149 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-06T11:12:15

The answer is $\frac{32}{\sqrt{82}}$ $32/sqrt82$

Explanation:

The distance from the point $(x_{0}, y_{0})$ $(x_0,y_0)$ to the line $a x + b y + c = 0$ $ax+by+c=0$
is $d = \frac{∣ a x_{0} + b y_{0} + c ∣}{\sqrt{a^{2} + b^{2}}}$ $d=(∣ax_0+by_0+c∣)/(sqrt(a^2+b^2))$
Here the line is $9 x - y - 3 = 0$ $9x-y-3=0$ and the point is $(- 3, 2)$ $(-3,2)$

$:. d=(∣-27-2-3∣)/sqrt(81+1)=32/sqrt82$

Science

Math

Humanities

... and beyond

How do you find the distance from the line with equation $y = 9 x - 3$ $y=9x-3$ to the point at (-3,2)?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the distance from the line with equation y=9x-3y=9x−3y=9x-3 to the point at (-3,2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you find the distance from the line with equation $y = 9 x - 3$ $y=9x-3$ to the point at (-3,2)?