How do you find the discriminant of $x^2+4x+3=0$ and use it to determine if the equation has one, two real or two imaginary roots?

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Answer 1 · 2017-03-07T22:39:44

$D=B^2-4AC$
Where $A,B,C$ are numbers from left to right in an ordered equation.

$D=4^2-4*1*3=16-12=4$

$D>0->$ two real solutions ( $x=-1andx=-3$ )
$D=0->$ one real solution
$D<0->$ two imaginary solutions
graph{x^2+4x+3 [-10.53, 5.27, -1.447, 6.45]}

How do you find the discriminant of x^2+4x+3=0x^2+4x+3=0 and use it to determine if the equation has one, two real or two imaginary roots?