How do you find the discriminant of $x^2+4x-1=0$ and use it to determine if the equation has one, two real or two imaginary roots?

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Answer 1 · 2017-06-27T19:22:40

The answer is given below.

In the equation

$x^2 + 4x - 1 = 0$

a = 1, b = 4, c = -1

Discriminant = $b^2 - 4ac$

=> $4^2 - 4 xx 1 xx (-1)$

=> $16 - 4$

=> $12$

As the discriminant is greater than zero it means that the equation has two distinct real roots.

How do you find the discriminant of x^2+4x-1=0x^2+4x-1=0 and use it to determine if the equation has one, two real or two imaginary roots?