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How do you find the discriminant of #x^2-2x+1=0# and use it to determine if the equation has one, two real or two imaginary roots?

1 Answer

Apr 10, 2017

The discriminant of an equation of the form, #y = ax^2+bx+c#, is:

#d = b^2-4(a)(c)# If #d{(=0", one real root"),( > 0", two real roots"),(<0", two imaginary roots"):}#

Explanation:

Given: #x^2-2x+1=0#

#a = 1, b = -2, and c = 1#

#d = b^2-4(a)(c)#

#d = (-2)^2-4(1)(1)#

#d = 0#, then one real root

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