How do you find the discriminant of $4x^2 +12x+9=0$ ?

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Answer 1 · 2016-12-13T08:31:58

See explanation.

For a quadratic equation $ax^2+bx+c=0$ the discriminant is defined as:

$Delta=b^2-4ac$

In the given equation we have:

$a=4$ , $b=12$ and $c=9$ , so:

$Delta=12^2-4*4*9=144-144=0$