How do you find the discriminant for $x^{2} - 9 x + 21 = 0$ $x^2-9x+21=0$ and determine the number and type of solutions?

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How do you find the discriminant for $x^{2} - 9 x + 21 = 0$ $x^2-9x+21=0$ and determine the number and type of solutions?

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Answer 1 · 2018-04-16T02:20:09

$Discriminant < 0, given equation has NO REAL ROOTS$ $color(crimson)("Discriminant " < 0, " given equation has " color(brown)("NO REAL ROOTS"$

Both the roots are Imaginary

Explanation:

$Discriminant < 0, given equation has NO REAL ROOTS$ $color(crimson)("Discriminant " < 0, " given equation has " color(brown)("NO REAL ROOTS"$

Standard form of quadratic equation is $a x^{2} + b x + c = 0$ $ax^2 + bx + c = 0$

$x^{2} - 9 x + 21$ $x^2 -9x + 21$

![https://newcollegeswindonmaths.wordpress.com/2016/04/10/core-1-discriminant/]( useruploads.socratic.org )

$a = 1, b = - 9, c = 21, D = b^{2} - 4 a c = {(- 9)}^{2} - (4 \cdot 1 \cdot 21) = - 3$ $a = 1, b = -9, c = 21, D = b^2 - 4ac = (-9)^2 - (4 * 1 * 21) = -3$

Since $Discriminant < 0, given equation has NO REAL ROOTS$ $color(crimson)("Discriminant " < 0, " given equation has " color(brown)("NO REAL ROOTS"$

Both the roots are Imaginary

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How do you find the discriminant for $x^{2} - 9 x + 21 = 0$ $x^2-9x+21=0$ and determine the number and type of solutions?

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Explanation:

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How do you find the discriminant for x2−9x+21=0x^2-9x+21=0 and determine the number and type of solutions?

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Explanation:

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How do you find the discriminant for $x^{2} - 9 x + 21 = 0$ $x^2-9x+21=0$ and determine the number and type of solutions?