How do you find the discriminant for $2.25 x^{2} - 3 x = - 1$ $2.25x^2-3x=-1$ and determine the number and type of solutions?

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How do you find the discriminant for $2.25 x^{2} - 3 x = - 1$ $2.25x^2-3x=-1$ and determine the number and type of solutions?

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Answer 1 · 2018-04-16T02:12:55

$b^{2} - 4 a c = 0, Given equation has one real repeated root - (\frac{2}{3})$ $color(violet)(b^2 - 4ac = 0, " Given equation has one real repeated root " -(2/3)$

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$2.25 x^{2} - 3 x + 1 = 0$ $2.25x^2 - 3x + 1 = 0$

$a = 2.25, b = - 3, c = 1$ $a = 2.25, b = -3, c = 1$

$D = b^{2} - 4 a c = {(- 3)}^{2} - (4 \cdot 2.25 \cdot 1) = 9 - 9 = 0$ $D = b^2 - 4ac = (-3)^2 - (4 * 2.25 * 1) = 9 - 9 = 0$

Since $b^{2} - 4 a c = 0, Given equation has one real repeated root$ $color(violet)(b^2 - 4ac = 0, " Given equation has one real repeated root "$

$and the root is = \frac{b}{2 a} = - \frac{3}{2 \cdot 2.25} = - \frac{3}{4.5} = - \frac{2}{3}$ $"and the root is " = b / (2a) = -3 / (2 * 2.25) = -3/4.5 = -2/3$

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How do you find the discriminant for $2.25 x^{2} - 3 x = - 1$ $2.25x^2-3x=-1$ and determine the number and type of solutions?

1 Answer

Explanation:

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How do you find the discriminant for $2.25 x^{2} - 3 x = - 1$ $2.25x^2-3x=-1$ and determine the number and type of solutions?