How do you find the discriminant for $0.5x^2-2x=-2$ and determine the number and type of solutions?

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Answer 1 · 2017-08-01T11:31:37

$D=0$ , so there is one root and the root is $2$

$0.5x^2 -2x = -2 or 0.5x^2 -2x +2 =0$

Comparing with standard quadratic equation $ax^2+bx+c=0$

We get here $a= 0.5 , b = -2 , c=2$

Discriminant $D= b^2-4ac = 4 - 4*0.5*2 = 4-4= 0$ We

know if $D >0$ two real roots , if $D = 0$ one real root. and

if $D < 0$ two complex roots. here $D=0$ so there is one root.

Root : $x = (-b +- sqrt D)/(2a) = 2 /(2*0.5)=2/1=2$ [Ans]

How do you find the discriminant for 0.5x^2-2x=-20.5x^2-2x=-2 and determine the number and type of solutions?