How do you find the discriminant and how many solutions does $x^{2} + 2 x + 7 = 0$ $x^2+2x+7=0$ have?

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Answer 1 · 2015-04-30T12:58:37

The equation is of the form $a x^{2} + b x + c = 0$ $color(blue)(ax^2+bx+c=0$ where:

$a = 1, b = 2, c = 7$ $a=1, b=2, c=7$

The Disciminant is given by :
$Delta=b^2-4*a*c$
$= (2)^2-4*1*7$
$= 4-28=-24$

If $Delta=0$ then there is only one solution.
(for $Delta>0$ there are two solutions,
for $Delta<0$ there are no real solutions)

As $Delta < 0$ , this equation has NO REAL SOLUTIONS

Note:
The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

How do you find the discriminant and how many solutions does x^2+2x+7=0x2+2x+7=0x^2+2x+7=0 have?