How do you find the discriminant and how many solutions does $r^{2} = 3 r + 0$ $r^2=3r+0$ have?

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How do you find the discriminant and how many solutions does $r^{2} = 3 r + 0$ $r^2=3r+0$ have?

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Answer 1 · 2015-05-09T04:05:32

Your equation, written as $r^{2} - 3 r = 0$ $r^2-3r=0$ is in the form: $a x^{2} + b x + c = 0$ $ax^2+bx+c=0$
Where:
$a = 1$ $a=1$
$b = - 3$ $b=-3$
$c = 0$ $c=0$
The discriminant is:
$Delta=b^2-4ac=9-4(1*0)=9>0$
Now, if:
1] $Delta>0$ you have 2 distinct Real solutions;
2] $Delta=0$ you have two Real coincident solutions;
3] $Delta<0$ you have no Real solutions.

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How do you find the discriminant and how many solutions does $r^{2} = 3 r + 0$ $r^2=3r+0$ have?

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