How do you find the discriminant and how many solutions does $7c^2 + 8c + 1 = 0$ have?

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Answer 1 · 2015-05-04T15:04:11

There is another way.

$7c^2 + 8c + 1 = 0.$

No need to solve this type of quadratic equation. Use shortcut.
Since a - b + c = 0, there are 2 real roots: (-1) and (-c/a = -1/7).

Reminder of shortcut:

a. When a + b + c = 0, one real root is (1) and the other is (c/a).

b. When a - b + c = 0, one real root is (-1) and the other is (-c/a).

How do you find the discriminant and how many solutions does 7c^2 + 8c + 1 = 07c^2 + 8c + 1 = 0 have?