How do you find the discriminant and how many solutions does $5w^2-2w+4=0$ have?

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Answer 1 · 2018-07-25T18:10:38

$b^2-4ac=-76$ , two complex conjugate roots

The given quadratic equation:

$5w^2-2w+4=0$

Comparing the above equation with the standard quadratic equation: $ax^2+bx+c=0$ we get

$a=5, b=-2$ & $c=4$

hence the discriminant $b^2-4ac$ of given quadratic equation is given as

$b^2-4ac=(-2)^2-4(5)(4)$

$=-76< 0$

$because b^2-4ac < 0$ hence given quadratic equation has two conjugate complex roots.

How do you find the discriminant and how many solutions does 5w^2-2w+4=0 5w^2-2w+4=0 have?