How do you find the discriminant and how many solutions does $4x^2-4x+11=0$ have?

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How do you find the discriminant and how many solutions does $4x^2-4x+11=0$ have?

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Answer 1 · 2015-05-06T01:36:51

The discriminant is given as:
$Delta=b^2-4ac$
In your equation (written in the general form: $ax^2+bx+c=0$ ) you have:
$a=4$
$b=-4$
$c=11$
So: $Delta=(-4)^2-4*(4*11)=-160<0$ This means that you cannot have REAL solutions to your equation (however, you can have two COMPLEX solutions!).

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How do you find the discriminant and how many solutions does $4x^2-4x+11=0$ have?

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