How do you find the discriminant and how many solutions does #4x^2-4x+11=0# have?

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How do you find the discriminant and how many solutions does #4x^2-4x+11=0# have?

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Answer 1 · 2015-05-06T01:36:51

The discriminant is given as:
#Delta=b^2-4ac#
In your equation (written in the general form: #ax^2+bx+c=0#) you have:
#a=4#
#b=-4#
#c=11#
So: #Delta=(-4)^2-4*(4*11)=-160<0# This means that you cannot have REAL solutions to your equation (however, you can have two COMPLEX solutions!).

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How do you find the discriminant and how many solutions does #4x^2-4x+11=0# have?

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