How do you find the discriminant and how many solutions does $4d^2 - 8d + 3= 0$ have?

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Answer 1 · 2015-04-30T19:04:56

Discriminant $D = d^2 = b^2 - 4ac = 64 - 48 = 16$ --> d = 4 and d = -4. There are 2 solutions, called real roots.

$x1 = -b/2a + d/2a = 8/8 + 4/8 = 12/8 = 3/2$

$x2 = -b/2a - d/2a = 8/8 - 4/8 = 4/8 = 1/2.$

How do you find the discriminant and how many solutions does 4d^2 - 8d + 3= 04d^2 - 8d + 3= 0 have?