How do you find the discriminant and how many solutions does $- 3 x^{2} + 7 x - 2 = 0$ $-3x^2+7x-2=0$ have?

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How do you find the discriminant and how many solutions does $- 3 x^{2} + 7 x - 2 = 0$ $-3x^2+7x-2=0$ have?

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Answer 1 · 2015-05-09T02:49:15

f(x) - 7x^2 + 7x - 2 = 0

D = d^2 = b^2 - 4ac = 49 - 24 = 25.-> d = +-5
There are 2 solutions (real roots)

$x 1 = \frac{7}{6} + \frac{5}{- 6} = \frac{2}{6} = \frac{1}{3}$ $x1 = 7/6 + 5/-6 = 2/6 = 1/3$
$x 2 = \frac{7}{6} - \frac{5}{- 6} = \frac{12}{6} = 2$ $x2 = 7/6 - 5/-6 = 12/6 = 2$

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How do you find the discriminant and how many solutions does $- 3 x^{2} + 7 x - 2 = 0$ $-3x^2+7x-2=0$ have?

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