How do you find the discriminant and how many solutions does $12x^2=x+6$ have?

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Answer 1 · 2015-05-09T16:10:05

Discriminant would be 289

If a quadratic is $a^2+bx+c$ . $b^2-4ac$ is called its discriminant. If the discriminant is $!=$ 0, then there would be two distinct solutions.

The discriminant of the given quadratic would be 1+288= 289

How do you find the discriminant and how many solutions does 12x^2=x+612x^2=x+6 have?