How do you find the discriminant and how many and what type of solutions does $x^{2} + 4 x + 4 = 0$ $x^2 +4x +4=0$ have?

Question

How do you find the discriminant and how many and what type of solutions does $x^{2} + 4 x + 4 = 0$ $x^2 +4x +4=0$ have?

1 Answer

Impact of this question

1431 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-10T18:15:19

discriminant $D = b^{2} - 4 a c$ $D= b^2 - 4ac$

we have equation :
$x^{2} + 4 x + 4 = 0$ $x^2 + 4x + 4 = 0$

here:
$a = 1$ $a =1$
$b = 4$ $b = 4$
$c = 4$ $c = 4$
(the coefficients of $x^{2}$ $x^2$ , $x$ $x$ and the constant term respectively)

finding $D$ $D$ :

$D = b^{2} - 4 a c = (4^{2}) - (4 \times 1 \times 4)$ $D= b^2 - 4ac = (4^2) - (4 xx 1 xx 4)$
$D = 16 - 16 = 0$ $D= 16 - 16 = 0$

formula for roots :
$x = \frac{- b \pm \sqrt{D}}{2 a}$ $x = (-b +- sqrt D) / (2a)$
$x = \frac{- 4 \pm \sqrt{0}}{2 \times 1}$ $x = (-4 +- sqrt 0) / (2 xx 1)$
$x = \frac{- 4 + 0}{2} and \frac{- 4 - 0}{2}$ $x = (-4 + 0) / 2 and (-4 - 0) /2$
$x$ $x$ has two equal solutions:
$x = - 2$ $x = -2$

the solutions are real and equal as $D = 0$ $D=0$

Science

Math

Humanities

... and beyond

How do you find the discriminant and how many and what type of solutions does $x^{2} + 4 x + 4 = 0$ $x^2 +4x +4=0$ have?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the discriminant and how many and what type of solutions does x^2 +4x +4=0x2+4x+4=0x^2 +4x +4=0 have?

1 Answer

Related questions

Impact of this question

How do you find the discriminant and how many and what type of solutions does $x^{2} + 4 x + 4 = 0$ $x^2 +4x +4=0$ have?