How do you find the discriminant and how many and what type of solutions does $6x^2-11x+3=0$ have?

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Answer 1 · 2015-04-30T19:25:59

Discriminant $D = d^2 = b^2 - 4ac = 121 - 72 = 49$ --> d = 7 and d = -7.
There are 2 solutions called 2 real roots.

$x1 = -b/(2a) + d/(2a)$ =

$x2 = -b/(2a) - d/(2a)$ =

How do you find the discriminant and how many and what type of solutions does 6x^2-11x+3=06x^2-11x+3=0 have?