How do you find the discriminant 2x^2+3x-9=0?

1 Answer
Feb 14, 2017

Discriminant is 81

Explanation:

2x^2+3x-9=0
Comparing with general quadratic equation ax^2+bx+c=0 we get a=2 ,b= 3 , c= -9
Disciminant is D=b^2-4ac or D= 3^2 -4 * 2* (-9) = 9 +72 = 81

If D >0 , there is 2 real solution.
If D =0 , there is 1 real solution.
If D<0 , there is no real solution , roots are imaginary.
Discriminant is 81 [Ans]