How do you find the derivative of #y=x(x^2+1)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Andrea S. Dec 30, 2016 #(dy)/(dx) = 3x^2+1# Explanation: As: #y=x(x^2+1) = x^3+x# we have: #(dy)/(dx) = 3x^2+1# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1721 views around the world You can reuse this answer Creative Commons License