How do you find the derivative of #y(x)= 6/(x-8)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Mia Oct 22, 2016 #y'(x)=(-6)/(x-8)^2# Explanation: We will find #y'(x)# based on derivative of rational function that says: #color(blue)((u/v)'=(u'v-v'u)/v^2# #color(blue)(y'(x)=((6)'(x-8)-(x-8)'*6)/(x-8)^2# #color(blue)(y'(x)=(0*(x-8)-1*6)/(x-8)^2# #color(blue)(y'(x)=(-6)/(x-8)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1645 views around the world You can reuse this answer Creative Commons License