How do you find the derivative of #y= (x+1) / (x-1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Eddie Jul 10, 2016 #= -( 2 )/((x-1)^2)# Explanation: Quotient Rule #(u/v)^prime = (u' v - u v')/(v^2)# here #u = x+1, v = x-1, u' = v' = 1# so we have # ((1) (x-1) - (x+1) (1))/((x-1)^2)# #= -( 2 )/((x-1)^2)# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 5383 views around the world You can reuse this answer Creative Commons License