How do you find the derivative of #y=e^x/x#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer GiĆ³ Feb 10, 2015 You can use the Quotinet Rule where: if #y=f(x)/g(x) -> y'=[f'(x)g(x)-f(x)g'(x)]/[g(x)]^2# So you get: #y'=(xe^x-1e^x)/x^2=# #=e^x(x-1)/x^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 4378 views around the world You can reuse this answer Creative Commons License