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How do you find the derivative of #y=5+sinx#?

1 Answer

Steve M · Andrea S.

Nov 28, 2016

#dy/dx=cosx#

Explanation:

#d/dx("constant") = 0 #

#d/dx(sinx) = cosx #

And so if #y=5+sinx => dy/dx=0+cosx=cosx#

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