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How do you find the derivative of #y = 4 / cosx#?

1 Answer

Jun 22, 2016

#4 sec x tan x#

Explanation:

#( 4 / cosx)' = 4 (( cosx)^{-1} )'#

#= 4 (-1( cosx)^{-2} (-sin x))#

#= 4 (1/( cosx)^{2} (sin x))#

#= 4 sec x tan x#

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