How do you find the derivative of #y=2/(3x^2)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Alan N. Mar 3, 2017 #dy/dx=-4/(3x^3)# Explanation: #y = 2/(3x^2) = 2/3x^-2# Applying the power rule: #dy/dx= 2/3*(-2)x^-3# #=-4/(3x^3)# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 4330 views around the world You can reuse this answer Creative Commons License