How do you find the derivative of #y=1/(1+e^x)#?

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How do you find the derivative of #y=1/(1+e^x)#?

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Answer 1 · 2017-09-22T01:07:26

#dy/dx=-e^x(1+e^x)^-2#

Explanation:

Differentiate using the chain rule
Given #y=f(g(x))#
#dy/dx=f'(g(x))*(g'(x)) larr#chain rule
#y=(1+e^x)^-1#
#dy/dx=(-(1+e^x)^-2)*e^x#
#=-e^x/(1+e^x)^2#

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How do you find the derivative of #y=1/(1+e^x)#?

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