How do you find the derivative of #(x-3) /( 2x+1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Eddie Jun 24, 2016 #= ( 7 )/( 2x+1)^2# Explanation: Use the quotient rule #((x-3) /( 2x+1))'# #= ((x-3)'( 2x+1) - (x-3)( 2x+1)' )/( 2x+1)^2# #= ((1)( 2x+1) - (x-3)( 2) )/( 2x+1)^2# #= ( 2x+1 - 2x+6 )/( 2x+1)^2# #= ( 7 )/( 2x+1)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1108 views around the world You can reuse this answer Creative Commons License