How do you find the derivative of #x^(1/2)#? Calculus Basic Differentiation Rules Power Rule 1 Answer Hubert May 28, 2015 Using the power rule: #(x^(1/2))'=1/2 * x^(1/2-1)=1/2 * x^(-1/2)=1/2 * 1/x^(1/2)=1/(2x^(1/2))# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 2239 views around the world You can reuse this answer Creative Commons License