How do you find the derivative of the function #f(x)=x^3-3x+5#?

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Answer 1 · 2016-12-07T10:26:42

The answer is #f'(x)=3x^2-3#

We use #(x^n)'=nx^(n-1)#

#f(x)=x^3-3x+5#

#(x^3)'=3x^2#

#(3x)'=3#

#(5)'=0#

so,

#f'(x)=3x^2-3#