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How do you find the derivative of #((t^(2)+1)/(t^(2)-1))#?

1 Answer

Aug 23, 2016

#f'(t) = (-4t)/(t^2-1)^2#

Explanation:

#f(t) = ((t^2+1)/(t^2-1))#

#f'(t) = ((t^2-1) (2t) - (t^2+1)(2t))/(t^2-1)^2# (Quotient rule)

#= (2t(t^2-1-t^2-1))/(t^2-1)^2#

#= (-4t)/(t^2-1)^2#

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