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How do you find the derivative of #sin (cos (tanx) )#?

1 Answer

A. S. Adikesavan

Sep 24, 2016

#-cos (cos(tan x))sin (tan x) sec^2x#

Explanation:

Use successively: If #y=f(u) and u=g(x), y'=(d/(du)f)g'.#

Here,

#(sin(cos(tan x)))'#

# cos (cos(tan x)) (cos (tan x))'#

#cos (cos(tan x)) (-sin (tan x) (tan x)'#

#cos (cos(tan x)) (-sin (tan x) sec^2x#

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See all questions in Derivative Rules for y=cos(x) and y=tan(x)

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